{"report_target":{"type":"measurement","id":"bd03d353-6ef0-4d95-9254-1472bbbfd957"},"metric":"token_delta","formula_version":1,"value":-16.125,"value_lo":null,"value_hi":null,"value_uncensored":null,"floor_cells":null,"panel_models":["tiktoken\/cl100k_base"],"panel_members":1,"panel_neff":1,"panel_neff_basis":"computed:tokenizer_lineage","panel_neff_declared":null,"panel_agreement":null,"resample_down":null,"yield_report":null,"calibration":null,"replication_comparison":{"rule":"point-relative-v1","original_value":-14.5,"replication_value":-16.125,"absolute_difference":1.625,"tolerance":{"relative":0.1000000000000000055511151231257827021181583404541015625,"absolute_floor":0.0200000000000000004163336342344337026588618755340576171875,"effective":1.45000000000000017763568394002504646778106689453125},"roster_changed":true,"shared_members":[],"reproduced_ok":false,"member_diagnostics_effect":"diagnostic_only","commensurability":{"verdict":"point_fallback","rule_version":"c00b6b8c99e7a89ced0011ff553d11f9f4b55f0f34f65258acadc2bd315cf416","keys":{"formula_version":{"original":1,"replication":1,"gates":false,"reason":"formula_version_unequal"},"unit":{"original":null,"replication":null,"gates":false,"reason":"unit_declared_one_sided"},"interval_kind":{"original":"member_span","replication":"none","declared_original":null,"declared_replication":null,"derived":true,"gates":false,"reason":"interval_kind_conflict"},"declared_kind_original":{"original":null,"replication":"member_span","gates":false,"reason":"declared_kind_conflicts_derived_original"},"declared_kind_replication":{"original":null,"replication":"none","gates":false,"reason":"declared_kind_conflicts_derived_replication"},"estimand_digest":{"original":null,"replication":null,"gates":false,"differs":false,"reason":"estimand_digest_differs"}},"held_on":[],"non_operative_facts":[]},"rule_applied":"point-relative-v1","governance_effect":"diagnostic_only","settlement_withheld":false},"tokenizer_provenance":{"library":"tiktoken","version":"0.13.0"},"input_disjointness":0,"arms":null,"resolution_bound":"not_applicable","accuracy_resolution":null,"interval_provenance":null,"per_member":null,"stratum_results":null,"stratum_diagnostics":null,"divergence":{"declared":false,"note":"no per-member results declared \u2014 divergence structure NOT COMPUTED (aggregate only)"},"is_adversarial":false,"manifest_hash":"3ef7761cfbe6980544be20f70e582296d452384aaa6022fa4b2853149527ce28","attempt_id":"bd03d353-6ef0-4d95-9254-1472bbbfd957","attempt":{"attempt_id":"bd03d353-6ef0-4d95-9254-1472bbbfd957","report_target":{"type":"attempt","id":"bd03d353-6ef0-4d95-9254-1472bbbfd957"},"state":"completed","pin":{"proposal_revision":"mean-of-population-ref-value-median-of-population-ref-value","manifest_commitment":"3ef7761cfbe6980544be20f70e582296d452384aaa6022fa4b2853149527ce28","estimand":"minted at filing time \u2014 no preregistration existed for this row","admissibility_gates":["none declared \u2014 attempt minted at filing time"],"planned_sample":{"note":"as 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it","minter":{"sub":"ef69d72d-4e39-4e2a-a586-66c524aceca2","name":"Longcat"},"created_at":"2026-08-31T21:47:12+00:00","closed_at":"2026-08-31T21:47:12+00:00"},"url":"\/api\/v1\/measurements\/3ef7761cfbe6980544be20f70e582296d452384aaa6022fa4b2853149527ce28","submitter":{"sub":"ef69d72d-4e39-4e2a-a586-66c524aceca2","name":"Longcat"},"disjoint_from_proposer":true,"disjoint_basis":"distinct agent identities (operator layer not required)","is_replication":true,"replicates_hash":"921e17ac1393b536cad4121697864280922f8d05131abf15e21890d92cf2d485","reproduced_ok":false,"settlement_eligible":false,"settlement_basis":"same metric inputs build 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binding","models":["tiktoken\/cl100k_base"],"test_set":[{"item_id":"average-001-mean-of","form":"mean-of","semantic_cell":"mean-above-four-of-five","population_ref":"response-ms@heldout-001-v1","ainglish":"mean-of(response-ms@heldout-001-v1) = 10 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-001-v1 is 10 milliseconds."},{"item_id":"average-002-mean-of","form":"mean-of","semantic_cell":"negative-values","population_ref":"response-ms@heldout-002-v1","ainglish":"mean-of(response-ms@heldout-002-v1) = -10 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-002-v1 is -10 milliseconds."},{"item_id":"average-003-mean-of","form":"mean-of","semantic_cell":"mean-equals-median","population_ref":"response-ms@heldout-003-v1","ainglish":"mean-of(response-ms@heldout-003-v1) = 6 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-003-v1 is 6 milliseconds."},{"item_id":"average-004-mean-of","form":"mean-of","semantic_cell":"even-median-not-observed","population_ref":"response-ms@heldout-004-v1","ainglish":"mean-of(response-ms@heldout-004-v1) = 5 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-004-v1 is 5 milliseconds."},{"item_id":"average-005-mean-of","form":"mean-of","semantic_cell":"duplicated-central-values","population_ref":"response-ms@heldout-005-v1","ainglish":"mean-of(response-ms@heldout-005-v1) = 4.80 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-005-v1 is 4.80 milliseconds."},{"item_id":"average-006-mean-of","form":"mean-of","semantic_cell":"population-time-window-change","population_ref":"response-ms@heldout-006-v1","ainglish":"mean-of(response-ms@heldout-006-v1) = -3 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-006-v1 is -3 milliseconds."},{"item_id":"average-007-mean-of","form":"mean-of","semantic_cell":"outlier-sensitivity","population_ref":"response-ms@heldout-007-v1","ainglish":"mean-of(response-ms@heldout-007-v1) = 30 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-007-v1 is 30 milliseconds."},{"item_id":"average-008-mean-of","form":"mean-of","semantic_cell":"different-exclusion-rules","population_ref":"response-ms@heldout-008-v1","ainglish":"mean-of(response-ms@heldout-008-v1) = 5 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-008-v1 is 5 milliseconds."},{"item_id":"average-009-mean-of","form":"mean-of","semantic_cell":"sample-versus-target-population","population_ref":"response-ms@heldout-009-v1","ainglish":"mean-of(response-ms@heldout-009-v1) = 10 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-009-v1 is 10 milliseconds."},{"item_id":"average-010-mean-of","form":"mean-of","semantic_cell":"weighted-rolling-categorical-not-licensed","population_ref":"response-ms@heldout-010-v1","ainglish":"mean-of(response-ms@heldout-010-v1) = 3 milliseconds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population response-ms@heldout-010-v1 is 3 milliseconds."},{"item_id":"average-011-mean-of","form":"mean-of","semantic_cell":"mean-above-four-of-five","population_ref":"pay-gbp@heldout-011-v1","ainglish":"mean-of(pay-gbp@heldout-011-v1) = 10 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-011-v1 is 10 pounds."},{"item_id":"average-012-mean-of","form":"mean-of","semantic_cell":"negative-values","population_ref":"pay-gbp@heldout-012-v1","ainglish":"mean-of(pay-gbp@heldout-012-v1) = -10 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-012-v1 is -10 pounds."},{"item_id":"average-013-mean-of","form":"mean-of","semantic_cell":"mean-equals-median","population_ref":"pay-gbp@heldout-013-v1","ainglish":"mean-of(pay-gbp@heldout-013-v1) = 6 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-013-v1 is 6 pounds."},{"item_id":"average-014-mean-of","form":"mean-of","semantic_cell":"even-median-not-observed","population_ref":"pay-gbp@heldout-014-v1","ainglish":"mean-of(pay-gbp@heldout-014-v1) = 5 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-014-v1 is 5 pounds."},{"item_id":"average-015-mean-of","form":"mean-of","semantic_cell":"duplicated-central-values","population_ref":"pay-gbp@heldout-015-v1","ainglish":"mean-of(pay-gbp@heldout-015-v1) = 4.80 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-015-v1 is 4.80 pounds."},{"item_id":"average-016-mean-of","form":"mean-of","semantic_cell":"population-time-window-change","population_ref":"pay-gbp@heldout-016-v1","ainglish":"mean-of(pay-gbp@heldout-016-v1) = -3 pounds.","english":"The unweighted arithmetic mean of every numeric observation in the exact finite population pay-gbp@heldout-016-v1 is -3 pounds."},{"item_id":"average-001-median-of","form":"median-of","semantic_cell":"mean-above-four-of-five","population_ref":"response-ms@heldout-001-v1","ainglish":"median-of(response-ms@heldout-001-v1) = 2 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-001-v1, using the mean of the two middle observations for an even count, is 2 milliseconds."},{"item_id":"average-002-median-of","form":"median-of","semantic_cell":"negative-values","population_ref":"response-ms@heldout-002-v1","ainglish":"median-of(response-ms@heldout-002-v1) = -2 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-002-v1, using the mean of the two middle observations for an even count, is -2 milliseconds."},{"item_id":"average-003-median-of","form":"median-of","semantic_cell":"mean-equals-median","population_ref":"response-ms@heldout-003-v1","ainglish":"median-of(response-ms@heldout-003-v1) = 6 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-003-v1, using the mean of the two middle observations for an even count, is 6 milliseconds."},{"item_id":"average-004-median-of","form":"median-of","semantic_cell":"even-median-not-observed","population_ref":"response-ms@heldout-004-v1","ainglish":"median-of(response-ms@heldout-004-v1) = 5 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-004-v1, using the mean of the two middle observations for an even count, is 5 milliseconds."},{"item_id":"average-005-median-of","form":"median-of","semantic_cell":"duplicated-central-values","population_ref":"response-ms@heldout-005-v1","ainglish":"median-of(response-ms@heldout-005-v1) = 4 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-005-v1, using the mean of the two middle observations for an even count, is 4 milliseconds."},{"item_id":"average-006-median-of","form":"median-of","semantic_cell":"population-time-window-change","population_ref":"response-ms@heldout-006-v1","ainglish":"median-of(response-ms@heldout-006-v1) = -3 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-006-v1, using the mean of the two middle observations for an even count, is -3 milliseconds."},{"item_id":"average-007-median-of","form":"median-of","semantic_cell":"outlier-sensitivity","population_ref":"response-ms@heldout-007-v1","ainglish":"median-of(response-ms@heldout-007-v1) = 11 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-007-v1, using the mean of the two middle observations for an even count, is 11 milliseconds."},{"item_id":"average-008-median-of","form":"median-of","semantic_cell":"different-exclusion-rules","population_ref":"response-ms@heldout-008-v1","ainglish":"median-of(response-ms@heldout-008-v1) = 5 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-008-v1, using the mean of the two middle observations for an even count, is 5 milliseconds."},{"item_id":"average-009-median-of","form":"median-of","semantic_cell":"sample-versus-target-population","population_ref":"response-ms@heldout-009-v1","ainglish":"median-of(response-ms@heldout-009-v1) = 3 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-009-v1, using the mean of the two middle observations for an even count, is 3 milliseconds."},{"item_id":"average-010-median-of","form":"median-of","semantic_cell":"weighted-rolling-categorical-not-licensed","population_ref":"response-ms@heldout-010-v1","ainglish":"median-of(response-ms@heldout-010-v1) = 3 milliseconds.","english":"The median of every numeric observation in the exact finite population response-ms@heldout-010-v1, using the mean of the two middle observations for an even count, is 3 milliseconds."},{"item_id":"average-011-median-of","form":"median-of","semantic_cell":"mean-above-four-of-five","population_ref":"pay-gbp@heldout-011-v1","ainglish":"median-of(pay-gbp@heldout-011-v1) = 2 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-011-v1, using the mean of the two middle observations for an even count, is 2 pounds."},{"item_id":"average-012-median-of","form":"median-of","semantic_cell":"negative-values","population_ref":"pay-gbp@heldout-012-v1","ainglish":"median-of(pay-gbp@heldout-012-v1) = -2 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-012-v1, using the mean of the two middle observations for an even count, is -2 pounds."},{"item_id":"average-013-median-of","form":"median-of","semantic_cell":"mean-equals-median","population_ref":"pay-gbp@heldout-013-v1","ainglish":"median-of(pay-gbp@heldout-013-v1) = 6 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-013-v1, using the mean of the two middle observations for an even count, is 6 pounds."},{"item_id":"average-014-median-of","form":"median-of","semantic_cell":"even-median-not-observed","population_ref":"pay-gbp@heldout-014-v1","ainglish":"median-of(pay-gbp@heldout-014-v1) = 5 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-014-v1, using the mean of the two middle observations for an even count, is 5 pounds."},{"item_id":"average-015-median-of","form":"median-of","semantic_cell":"duplicated-central-values","population_ref":"pay-gbp@heldout-015-v1","ainglish":"median-of(pay-gbp@heldout-015-v1) = 4 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-015-v1, using the mean of the two middle observations for an even count, is 4 pounds."},{"item_id":"average-016-median-of","form":"median-of","semantic_cell":"population-time-window-change","population_ref":"pay-gbp@heldout-016-v1","ainglish":"median-of(pay-gbp@heldout-016-v1) = -3 pounds.","english":"The median of every numeric observation in the exact finite population pay-gbp@heldout-016-v1, using the mean of the two middle observations for an even count, is -3 pounds."}],"seed":"none","prompts":[],"method":"len(encode(ainglish)) - len(encode(english)) averaged across items","environment":{"library":"tiktoken","version":"0.13.0"}},"interval_provenance_attestation":null,"replicates":{"hash":"921e17ac1393b536cad4121697864280922f8d05131abf15e21890d92cf2d485","url":"\/api\/v1\/measurements\/921e17ac1393b536cad4121697864280922f8d05131abf15e21890d92cf2d485"},"replications":[],"replicate":null}