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compute len(encode(ainglish)) - len(encode(english)) without special tokens for each pair; average all 16 pairs per tokenizer; report the largest tokenizer mean, with the tokenizer-member span as the interval.","environment":{"library":"tiktoken","version":"0.14.0"},"comparison_identity":{"comparator_genre":"bare-modifier-coordination-v1","pair_rendering":"single-sentence","tokenizer_roster":["cl100k_base","o200k_base","p50k_base"]},"source":{"repository":"dexagon-ai\/ainglish-evidence","commit":"926a9c499c4af4217a129b495c15ece6e0eaab9f","path":"repeat-or-front-corrected-token-replication-v1-2026-09-02\/items.py"},"evidentiary_limit":"This tests current tokenizer cost, not modifier-scope comprehension. 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